(DETAILED NOTES โ NCERT BASED)
1๏ธโฃ What is a Quadratic Equation?
An equation of the form ax2+bx+c=0ax^2 + bx + c = 0ax2+bx+c=0 where
- a,b,ca, b, ca,b,c are real numbers
- aโ 0a \neq 0a๎ =0
is called a quadratic equation in one variable.
Why โQuadraticโ?
Because the highest power of the variable is 2.
2๏ธโฃ Examples of Quadratic Equations
โ x2+7x+10=0x^2 + 7x + 10 = 0x2+7x+10=0
โ 2x2โ3x+5=02x^2 โ 3x + 5 = 02ร2โ3x+5=0
โ โ4x2+9=0-4x^2 + 9 = 0โ4ร2+9=0
โ Not quadratic:
- x3+2x+1=0x^3 + 2x + 1 = 0x3+2x+1=0 (degree 3)
- 5xโ2=05x โ 2 = 05xโ2=0 (linear)
3๏ธโฃ Standard Form of Quadratic Equation
ax2+bx+c=0ax^2 + bx + c = 0ax2+bx+c=0
Where:
- aaa โ coefficient of x2x^2x2
- bbb โ coefficient of xxx
- ccc โ constant term
โ ๏ธ If a=0a = 0a=0, the equation is not quadratic.
4๏ธโฃ Roots (Solutions) of a Quadratic Equation
The values of x that satisfy the equation are called its roots.
A quadratic equation always has two roots
(these roots may be real or imaginary).
5๏ธโฃ Methods of Solving Quadratic Equations
There are three methods prescribed in Class 10:
๐น Method 1: Factorisation Method
When to use?
โ When the equation can be factorised easily.
Steps:
- Write the equation in standard form.
- Split the middle term.
- Factorise.
- Set each factor equal to zero.
- Solve.
Example:
Solve: x2+5x+6=0x^2 + 5x + 6 = 0x2+5x+6=0x2+3x+2x+6=0x^2 + 3x + 2x + 6 = 0x2+3x+2x+6=0 (x+3)(x+2)=0(x + 3)(x + 2) = 0(x+3)(x+2)=0 x=โ3,ย โ2x = -3,\ -2x=โ3,ย โ2
๐น Method 2: Completing the Square Method
Important Concept:
Any expression of the form
(x+a)2=x2+2ax+a2(x + a)^2 = x^2 + 2ax + a^2(x+a)2=x2+2ax+a2
Steps:
- Make coefficient of x2=1x^2 = 1x2=1
- Move constant term to RHS
- Add square of half of coefficient of x
- Write LHS as a perfect square
- Solve
Example:
Solve: x2+6x+5=0x^2 + 6x + 5 = 0x2+6x+5=0x2+6x=โ5x^2 + 6x = -5x2+6x=โ5
Add 999 to both sides:(x+3)2=4(x + 3)^2 = 4(x+3)2=4 x+3=ยฑ2x + 3 = \pm 2x+3=ยฑ2 x=โ1,ย โ5x = -1,\ -5x=โ1,ย โ5
๐น Method 3: Quadratic Formula (MOST IMPORTANT)
Formula:
x=โbยฑb2โ4ac2ax = \frac{-b \pm \sqrt{b^2 โ 4ac}}{2a}x=2aโbยฑb2โ4acโโ
This method always works, even when factorisation fails.
Example:
Solve: 3x2โ5xโ2=03x^2 โ 5x โ 2 = 03ร2โ5xโ2=0
Here:
- a=3a = 3a=3
- b=โ5b = -5b=โ5
- c=โ2c = -2c=โ2
x=5ยฑ25+246x = \frac{5 \pm \sqrt{25 + 24}}{6}x=65ยฑ25+24โโ x=5ยฑ76x = \frac{5 \pm 7}{6}x=65ยฑ7โ x=2,ย โ13x = 2,\ -\frac{1}{3}x=2,ย โ31โ
6๏ธโฃ Discriminant
The expressionD=b2โ4acD = b^2 โ 4acD=b2โ4ac
is called the discriminant.
Importance:
The discriminant tells us the nature of roots without solving.
Nature of Roots Table:
| Value of D | Nature of Roots |
|---|---|
| D>0D > 0D>0 | Two real & distinct roots |
| D=0D = 0D=0 | Two real & equal roots |
| D<0D < 0D<0 | No real roots |
Example:
For x2โ4x+4=0x^2 โ 4x + 4 = 0x2โ4x+4=0D=(โ4)2โ4(1)(4)=0D = (-4)^2 โ 4(1)(4) = 0D=(โ4)2โ4(1)(4)=0
Roots are real and equal.
7๏ธโฃ Relationship Between Roots and Coefficients
Let roots be ฮฑ\alphaฮฑ and ฮฒ\betaฮฒ
For ax2+bx+c=0ax^2 + bx + c = 0ax2+bx+c=0:ฮฑ+ฮฒ=โba\alpha + \beta = \frac{-b}{a}ฮฑ+ฮฒ=aโbโ ฮฑฮฒ=ca\alpha \beta = \frac{c}{a}ฮฑฮฒ=acโ
8๏ธโฃ Forming a Quadratic Equation
If sum and product of roots are given:x2โ(ฮฑ+ฮฒ)x+ฮฑฮฒ=0x^2 โ (\alpha + \beta)x + \alpha\beta = 0x2โ(ฮฑ+ฮฒ)x+ฮฑฮฒ=0
Example:
Roots: 3 and 5x2โ8x+15=0x^2 โ 8x + 15 = 0x2โ8x+15=0
9๏ธโฃ Applications of Quadratic Equations (Word Problems)
Common topics:
โ Consecutive integers
โ Area & dimensions
โ Speed, distance, time
โ Age problems
Example:
The product of two consecutive positive integers is 156.
Let numbers be xxx and x+1x+1x+1x(x+1)=156x(x+1) = 156x(x+1)=156 x2+xโ156=0x^2 + x โ 156 = 0x2+xโ156=0
Solve using quadratic formula.
๐ Important Exam Points โญ
โ Always write standard form
โ Mention values of a, b, c
โ Show discriminant clearly
โ Use quadratic formula if factorisation is difficult
โ Do not forget ยฑ sign
๐ Summary
- Quadratic equation โ degree 2
- Standard form โ ax2+bx+c=0ax^2 + bx + c = 0ax2+bx+c=0
- Three solving methods
- Discriminant decides nature of roots
- Very important chapter for board exams
